How do I solve simultaneous equations like 2x + 5y = 50 and 3x + y = 23?

With simultaneous equations like these, you first want to get to a point where you have one equation with only one variable. To do this, you must eliminate one of the variables. In this case, if you multiply both sides of the second equation by 5, you get 15x + 5y = 115. Both equations now have a 5y term in them, so you can take one away from the other and eliminate the variable y:
15x + 5y = 115-(2x + 5y = 50)
13x + 0y = 65
65 / 13 = 5, so x = 5. We can now plug this value back into either of the original equations to find y. Using the second equation (before we multiplied it by 5), we get:
3 * 5 + y = 2315 + y = 23y = 8
So x = 5 and y = 8

AH
Answered by Alfie H. Maths tutor

1928 Views

See similar Maths 13 Plus tutors

Related Maths 13 Plus answers

All answers ▸

Simplify: 4 - 2x + x2 + 2x + 4


Solve: 7x - 20 = 3x + 4


Factorise 3𝑝𝑞4 − 12𝑞2𝑝6 fully.


How do I know which calculation to do first in questions with multiple operations (e.g. 2 x 3 - 2 x 5)?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning