Write x^2+6x-7 in the form (x+a)^2+b where a and b are integers

Complete the square.We want a quadratic we can simplify.Halve the linear term coefficient (6) and square it.Add it to the (x2+6x) term and subtract it from the 7.x2+6x+(6/2)2-7-(6/2)2As you can see the equation still holds true as the +(6/2)2 and -(6/2)2 cancels out.Gives x2+6x+9-7-9x2+6x+9 simplifies to (x+3)(x+3) or (x+3)2Left with (x+3)2-16

GB
Answered by George B. Maths tutor

18328 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve 7x=4(x-8)


How do you use the completing the square method to solve a quadratic equation?


A curve is given by the equation y=x^3-11x^2+28x; find the coordinates of the points where the curve touches the x-axis.


solve for x: (x-2)(x+3)=2(2x+11)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning