Write x^2+6x-7 in the form (x+a)^2+b where a and b are integers

Complete the square.We want a quadratic we can simplify.Halve the linear term coefficient (6) and square it.Add it to the (x2+6x) term and subtract it from the 7.x2+6x+(6/2)2-7-(6/2)2As you can see the equation still holds true as the +(6/2)2 and -(6/2)2 cancels out.Gives x2+6x+9-7-9x2+6x+9 simplifies to (x+3)(x+3) or (x+3)2Left with (x+3)2-16

GB
Answered by George B. Maths tutor

18335 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A bag has 3 red balls and 5 green balls. I take out 2 balls, without replacing them. What is the probability of choosing at least one red ball? Give your answer to 3 decimal places.


Solve x^2+2x-4, leaving your answer in the simplist surd form. (4marks)


How to expand double brackets?


write ( 4 x 10^-3) x ( 9 x 10^14) in standard form


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning