A ball is thrown in the air with velocity of 50.0 m/s, assuming no air resistance calculate its maximum height.
Use SUVAT equations to find height, S, when final velocity, V, is 0: s = ?u = 50 m/sv = 0 m/sa = -9.81 m/st = Not necessaryRecall: v2 = u2 +2as s = -u2/(2a) = -2500/(2 x -9.81) = 127.4 m But given to 3 sig figs so s = 127 m
OG
Related Physics A Level answers
All answers ▸A ball is thrown at speed u = 10.0 m/s at an angle of 30.0 degrees to the ground at height, s = 0. How far does the ball travel horizontally from its starting position? (Ignore air resistance and taking g = 9.81 m/s^2)
An ideal gas within a closed system undergoes an isothermal expansion from an initial volume of 1m^3 to 2m^3. Given that the initial pressure of the gas is 10^5 Pa, find the final pressure of the gas following the expansion.
Describe, using a diagram, the forces acting on the system of an object tethered to a string, rotating around a fixed point in free space. Will the string ever become horizontal?
Describe simple harmonic motion (SHM). Sketch a displacement-time graph for a particle undergoing SHM and the corresponding velocity-time and acceleration-time graphs. Use these graphs to describe the relationship between accleration and displacment.