Solve the Simultaneous equations. 3x+5y=22 4x-5y=6

3x+5y=224x-5y=6Our first task is to cancel out one of the variables. So you see that both y variables have a 5 before them. As one has -5 and the other has +5 you can add both simultaneous equations together to cancel out the y's. this gives us the result:7x +0y = 28 -> 7x=28. Then to find the value of "x" we divide both sides by 7 giving us x = 4. Then to find out the value of y we substitute the value of x back into either of the equations. Lets choose 3x+5y=22. Subbing in x=4 gives us 3*4+5y=22 -> 12+5y=22. Subtracting 12 from both sides gives 5y = 10. Then dividing both sides by 5 gives y = 2. Therfore the solution to these equations is x=4 and y=2

CL
Answered by Chris L. Maths tutor

4160 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

If you are given the function f(x) = 10-3x and g(x) = (x-3)/2 , find the value of the composite function gf(4) ?


How to factorise x^2 + 6x +5


A group of 5 people order 2 8 inch pizzas, with heights 2cm and 1cm, and density 3/pi g/cm^3, and 5/pi g/cm^3 respectively. If they divide each pizza evenly, how much pizza, in grams, does each person eat? Use 1 inch = 2.5 cm.


A group of 55 students were asked if they had a cat or a dog. 11 were known to own both, 18 said they owned only a dog, and 34 said they owned at least a cat. Give the probability that a student has neither as a fraction in its simplest form.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning