Solve the Simultaneous equations. 3x+5y=22 4x-5y=6

3x+5y=224x-5y=6Our first task is to cancel out one of the variables. So you see that both y variables have a 5 before them. As one has -5 and the other has +5 you can add both simultaneous equations together to cancel out the y's. this gives us the result:7x +0y = 28 -> 7x=28. Then to find the value of "x" we divide both sides by 7 giving us x = 4. Then to find out the value of y we substitute the value of x back into either of the equations. Lets choose 3x+5y=22. Subbing in x=4 gives us 3*4+5y=22 -> 12+5y=22. Subtracting 12 from both sides gives 5y = 10. Then dividing both sides by 5 gives y = 2. Therfore the solution to these equations is x=4 and y=2

CL
Answered by Chris L. Maths tutor

4441 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

An exam has two papers. Alan scores: 33 out of 60 on paper 1 & 75 out of 100 on paper 2. Work out his percentage score for the exam?


Solve x^2+4x-5=0 by completing the square.


A,B,C and D are points on a circle. ABCD is a square of side 7 cm. Work out the total area of the shaded regions. Give your answer correct to the nearest whole number.


Work out 5/6 + 3/7. Give your answer as a mixed number.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning