If a ball is thrown at a velocity of 5m/s, what height does it reach?
For this, we use the conservation of energy. We know that loss of kinetic energy = gain in potential energy, so KE = PE. Our equation is 0.5mv2 = mgh, but as we have m on both sides, this cancels. So, we are left with 0.5v2 = gh, and to find h = 0.5*v2/g = 0.5 * 52 / 9.81 = 1.274... m. So, the height the ball reaches is 1.27 m (to 3 sig. fig.).
LU
Related Physics GCSE answers
All answers ▸A kettle requires 2400 Coulombs of charge to pass through its heating element, with a resistance of 6 Ohms, in a time of 200 seconds in order to boil the water inside it. Calculate the current flowing and the power of the kettle.
A person swims from a depth of 0.50 m to a depth of 1.70 m below the surface of the sea. Density of the sea water = 1030 kg/m^3. Gravitational field strength = 9.8 N/kg. Calculate the increase in pressure on the swimmer. Give the unit.
Is momentum a vector or a scalar quantity?
How do I solve this problem?