To solve this quadratic equation we should first see if it is possible to factorise it into two seperate brakets. In this case there are no numbers which multiply to give -5 and add to give 3. Thus we should resort to using the quadratic formula which is used when equations cannot be solved by inspection. The quadratic formula is x=(-b+-(b²-4ac)^1/2)/2a. Values for a,b and c can be lifted from the question. ax²+b-c=0 so in this question a=3 b=1 and c=-5. Inputing these into the equation will give two results. The answers are x=1.135 or x=-1.468 both of these answers make the original equation true.