A curve has the equation x^2 +2x(y)^2 + y =4 . Find the expression dy/dx in terms of x and y [6]

Integrate each term in terms of x, then integrate each term in terms of y Make sure you state in what form you are integrating. Remember if you are integration in terms of y, the x values are constants and vice versa 2x + 2(y^2) + (2x*2y)dy/dx + 1dy/dx = 0 2x + 2(y^2) + (4xy +1) dy/dx = 0 [4](4xy +1) dy/dx = -(2x + 2(y^2) )Therefore dy/dx = -(2x + 2(y^2) ) / (4xy +1) [2]

LC
Answered by Lavana C. Maths tutor

3640 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Integrate (3x^2 - (1/4)x^-2 + 3) dx


For a curve of equation 2ye^-3x -x = 4, find dy/dx


Particle A mass 0.4kg and B 0.3kg. They move in opposite direction and collide. Before collision, A had speed 6m/s and B had 2m/s. After collision B had 3m/s and moved in opposite direction. Find speed of A after collision with direction and Impulse on B.


Find the stationary points of y = (x-7)(x-3)^2.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning