A curve has the equation x^2 +2x(y)^2 + y =4 . Find the expression dy/dx in terms of x and y [6]
Integrate each term in terms of x, then integrate each term in terms of y Make sure you state in what form you are integrating. Remember if you are integration in terms of y, the x values are constants and vice versa 2x + 2(y^2) + (2x*2y)dy/dx + 1dy/dx = 0 2x + 2(y^2) + (4xy +1) dy/dx = 0 [4](4xy +1) dy/dx = -(2x + 2(y^2) )Therefore dy/dx = -(2x + 2(y^2) ) / (4xy +1) [2]
LC
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