Sketch the graph of y= (x^2) -2x -3 labelling the turning points and points of intersection

The gradient of the curve equals the first derivative.dy/dx = 2x - 2At the turning point the gradient equals zero.2x -2 = 02x = 2 x= 1to find the y co-ordinate to this point substitute x = 1 into the original expressiony = 1^2 -(2x1) -3 = 1-2-3 = -4 Therefore the tuning point is (1,-4)To find the y intercept x=0y = 0^2 -(0x1) -3 = -3 therefore coordinates (0,-3)To find the x intercept y = 00= x^2 -2x -3 by observation (x-3)(x+1) = 0 therfore x= 3 and -1the corordinateds are (-1, 0) (3,0)Mark the points above and use them to help you plot the curve, remembering to add labels.As this is an x^2 graph with a positive coefficient of x^2 we know this curve will be an upright U shaped curve