How is an action potential fired?

When a neurone is at rest, the outside of the neurone is more positive than the inside. This is due to the sodium-potassium pump which actively pumps 3 Na+ outside the cell, whilst at the same time pumping 2 K+ inside the cell. This creates a potential difference of -70mV, known as the resting potential. If a receptor is stimulated, there is a change in the permeability of the membrane, as Na+ channels open, allowing many Na+ ions to move into the cell, down a concentration gradient. This is called depolarisation, and causes the inside of the cell to become more positive than the outside. If the potential difference reaches about -50mV, an action potential will be fired. This is known as the threshold value. The potential difference keeps increasing until it reaches about +40mV. At this point, the Na+ channels close, and K+ channels open allowing K+ to leave the cell. The cell becomes repolarised, as the potential difference decreases and approaches the resting potential. However, the potential difference goes slightly below the resting potential, as there is a slight delay before the K+ channels close. This is called hyperpolarisation. The potential difference then returns to the resting potential.

EB
Answered by Eleanor B. Biology tutor

4109 Views

See similar Biology A Level tutors

Related Biology A Level answers

All answers ▸

What exactly causes the sounds heard by a stethoscope


Where did mitochondria come from?


How do I answer a long answer question in detail without writing too much and wasting exam time?


Describe how vaccination can lead to protection against bacterial meningitis (6 marks)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences