How do I rewrite 2 cos x + 4 sin x as one sin function?

This question makes use of the sin addition formula. It may be stated as sin (A + B) = sinA cosB + sinB cosA . We want to rewrite 2 cosx + 4 sinx in the form R sin (x + a), so firstly work out what R sin(x +a) is, expanded. By using the formula above, we get R sin(x + a) = Rinxcosa + Rsinacosx or (R cos a) sinx + (R sin a) cosx, where the parts in the brackets are the constants.
We can therefore equate the constants to the constants given in the original expression, i.e. 4 and 2, so we get that R cos a = 4 and R sin a = 2. Making use of two more trig formulae, we can work out what R and a are. For example. cos^2 x + sin^2 x = 1, meaning R = sqrt (R cos^2 a + R sin^2 a). To work out a, use tan a = sin a / cos a.

SS

Related Maths A Level answers

All answers ▸

p(x)=2x^3 + 7x^2 + 2x - 3. (a) Use the factor theorem to prove that x + 3 is a factor of p(x). (b) Simplify the expression (2x^3 + 7x^2 + 2x - 3)/(4x^2-1), x!= +- 0.5


A Polynomial is defined as X^3-6X^2+11X-6. a)i Use the factor theorem to show that X-3 is a factor. ii Express as a linear and quadratic b)Find the first and second derivative c) Prove there is a maximum at y=0.385 to 3DP


Differentiate the function f(x) = 2x^3 + (cos(x))^2 + e^x


Using the equation cos(a+b) = cos(a)cos(b) - sin(a)sin(b) or otherwise, show that cos(2x) = 2cos^2(x) - 1.