Given df/dx=2x+3 and the graph goes through (1,1), what is the function f?

First step: integrate int df/dx = x^2+3x+c (never forget the constant!) 

Second step: substitute the point in order to get c 

1 = (1)^2+3*1+c -> c = 1-1-3=-3

Thus, f = x^2+3x-3

EG
Answered by Evita G. Maths tutor

4391 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I integrate tan^2 x?


x = 3t - 4, y = 5 - (6/t), t > 0, find "dy/dx" in terms of t


What are differences between speed and velocity, velocity and speed and acceleration?


How can do you factorize the equation x^2+6x+8


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences