Given y(x+y)=3 evaluate dy/dx when y=1

y(x+y)=3,yx +y2 =3,Differentiating with respect to x,y+x(dy/dx) +2y(dy/dx)=0when y=1, x=3-1=2 (from original equation)1+2(dy/dx) +2(dy/dx)=0,dy/dx=-1/4

LP
Answered by Leto P. Maths tutor

4291 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

f(x) is defined by f(x) = 3*x^3 + 2*x^2 - 7*x + 2. Find f(1).


Differentiate y= (2x+1)^3. [The chain rule]


A curve has equation y = f(x) and passes through the point (4, 22). Given that f'(x) = 3x^2 - 3x^(1/2) - 7, use integration to find f(x), giving each term in its simplest form


Find the area under the curve with equation y = 5x - 2x^2 - 2, bounded by the x-axis and the points at which the curve reach the x-axis.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences