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### Solve the simultaneous equations 3x + 4y = 17 and 4x + y = 14

Eq1: 3x + 4y = 17

Eq2: 4x + y = 14

Eq2 x 4: 16x + 4y = 56

Subtract Eq1 from this to isolate x: 16x + 4y - 3x - 4y = 56 - 17

Simplify: 13x = 39

Solve for x: x = 3

Substitute x into Eq1: 3(3) + 4y = 17

9 + 4y = 17

4y = 8

y = 2

Check in Eq2: 4(3) + (2) = 14

12 + 2  = 14

2 years ago

Answered by David, a GCSE Maths tutor with MyTutor

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