The recommended daily allowance of methionine for an adult is 15 mg per kg of body mass. Tuna contains 755 mg of methionine per 100 g portion. Calculate the mass, in grams, of tuna that would provide the RDA of methionine for a 60 kg adult.
15mg per kilo recommended dose 15x60 = 900mg recommended dose for a 60kg adult There is 755mg per 100g portion of tuna So 900/755 = 1.19 times the amount in 100g of tuna is the recommended dose 1.19 x 100 = 119 119g of tuna is the amount that would provide the total recommended dose for a 60kg adult
DC
Related Chemistry A Level answers
All answers ▸Differences between Sn1 and Sn2 reactions
How do you work out an electron configuration?
How can one differentiate between the organic compounds propanal (CH3CH2CHO) and propanone (CH3COCH3)?
Calculate the amount (in moles) of iron 3 nitrate in a 2.16g sample.