The recommended daily allowance of methionine for an adult is 15 mg per kg of body mass. Tuna contains 755 mg of methionine per 100 g portion. Calculate the mass, in grams, of tuna that would provide the RDA of methionine for a 60 kg adult.

15mg per kilo recommended dose 15x60 = 900mg recommended dose for a 60kg adult There is 755mg per 100g portion of tuna So 900/755 = 1.19 times the amount in 100g of tuna is the recommended dose 1.19 x 100 = 119 119g of tuna is the amount that would provide the total recommended dose for a 60kg adult

DC
Answered by Darragh C. Chemistry tutor

5897 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

Explain the polarity of both CH3CH2Br and CBr3CBr3.


What is a stereoisomer?


What is an isomer?


pH and Kw question: A student dissolves 1.75g of a drain cleaner (based on NaOH) in water and makes the solution up to 100cm3. The student measures the solution pH as 13.60. Determine the percentage of NaOH in the drain cleaner, in terms of mass (g).


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning