The recommended daily allowance of methionine for an adult is 15 mg per kg of body mass. Tuna contains 755 mg of methionine per 100 g portion. Calculate the mass, in grams, of tuna that would provide the RDA of methionine for a 60 kg adult.
15mg per kilo recommended dose 15x60 = 900mg recommended dose for a 60kg adult There is 755mg per 100g portion of tuna So 900/755 = 1.19 times the amount in 100g of tuna is the recommended dose 1.19 x 100 = 119 119g of tuna is the amount that would provide the total recommended dose for a 60kg adult
DC
Related Chemistry A Level answers
All answers ▸How do you convert between different SI units, for example, nmol to mmol?
What is Hund's rule?
The ratio between the molar mass of an alkene(A) and an alkyne(B) with the same number of carbon atoms is 1.05. Find the molecular formulas of the two hydrocarbons then write the reaction for how we can obtain the alkene A from the alkyne B.
Discuss the trend in first ionisation energies across the second period of the periodic table.