There are 200 students in Year 10. 110 are boys. There are 250 students in Year 11. 140 are boys. Which year has the greater proportion of boys?

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Let P1 and P2 be the proportion of boys in each year.

In order to compare them we should pur the two proportions into simple forms.

P1 = (Number of boys) / (Total number of students)

P1 = 110 / 200 and, simplifying the fraction by 10 we get 

P1 = 11 / 20

Similarily, P2 = 140 / 250 = 14 / 25

Now we need to compare 11/20 with 14/25

In the first fraction, we multiply both the numerator and the denominator by 5 to get

11/20 = 55 / 100 = 55%

Similarily, we multiply the second fraction by 4, getting

14/25 = 56/100 = 56%

Therefore, the first proportion is greater than the other.

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