Differentiate y=3xe^{3x^2}+2x
We differentiate y with respect to x:Firstly, we apply the Chain rule in the fist part of the RHS. Remembering the chain rule is uv -> u'v+uv', so d(3xe^{3x^2})/dx=3e^{3x^2}+18x^{2}e^{3x^2}now, we simply differentiate 2x to 2.Now combining our results:dy/dx = 3e^{3x^2}+18x^{2}e^{3x^2} + 2
Typically 4/5 marks for AS-level papers.
JA
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