Find the gradient at x=1 for the curve y=2x*e^2x

The answer to this question is in two parts. We firstly must find the derivative of the function y=f(x) with respect to x, and then substitute the value of x given in the question to find the gradient at that point.To find the derivative of the function, we use both the product and chain rule. we see that dy/dx =4xe^2x+2e^2x using these rules for differentiation.we now substitute x=1 into this to find the gradient as 6e^2 at this point.

DD
Answered by Dominic D. Maths tutor

4687 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the first derivative of f(x). f(x) = ln(3x^2+2x+1)


The curve C has the equation y=((x^2+4)(x-3))/2*x where x is not equal to 0 . Find the tangent to the curve C at the point where x=-1 in the form y=mx+c


Differentiate the function f(x)=2xsin3x


a curve is defined by y=2x^2 - 10x +7. point (3, -5) lies on this curve. find the equation of the normal to this curve


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning