solve; (6x - 2)/2 - (4x+7)/3 = 1-x

numerical answer x =-1/8 oe (or equivalent), but I am more interested in the method usedMy methodsimplify first fraction to 3x-1, multiply both sides by 3, collect like terms, divide through to get x on its own1 anticipated alternativemake LHS common denominator, multiply through, collect and simplify I anticipate a student may also have an alternative attempt, if the student is comfortable and reliable in this method if their working is logical and it is of appropriate length for an exam situation this is absolutely acceptable, I would usually demonstrate how I would approach it as well unless I felt this could confuse them.