A trolley of negilible mass on horizontal tracks is at rest. A person of mass 50kg is standing on the trolley with a bag of mass 10kg. The person throws the bag off the trolley horizontally with a velocity of 3m/s. Calculate the velocity of the man.

Establish what information you have been given in the question (mass of person=50kg, mass of bag=10kg, velocity of bag=3m/s, start velocity of both=0m/s). Use the equation momentum=mv and the principle of conservation of momentum. This means that the initial momentum of the man and bag is 0 as they are stationary. Therefore mass of bag * 3 = mass of man * v. Solve for v to get 0.6m/s.

EC
Answered by Ella C. Maths tutor

3080 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The line AB has equation 5x + 3y + 3 = 0. The line AB is parallel to the line y = mx + 7. Find the value of m.


Differentiate with respect to x, x^2*e^(tan(x))


Use logarithms to solve the equation 3^(2x+1) = 4^100


How do I differentiate (e^(2x)+1)^3?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning