Answers>Maths>IB>Article

Differentiate, from first principles, y=x^2

According to first principles, the differential is found as the limit as h->0 of:[f(x+h)-f(x)] / hif we set our f to x^2, then we find that this expression becomes (x^2+2hx+h^2 - x^2)/hWhich simplifies to 2x+h. As h->0, this leaves us with 2x, which is the derivative of x^2

ME
Answered by Milo E. Maths tutor

2523 Views

See similar Maths IB tutors

Related Maths IB answers

All answers ▸

How to find the derivative of sqrt(x) from first principles?


Factorise z^3+1 into a linear and quadratic factor. Let y=(1+i√3)/2. Show that y is a cube root of -1. Show that y^2=y-1. Find the value of (1-y)^6.


Given that y = arcos(x/2) find dy/dx of arccos(x/2) and hence find the integral from 0 to 1 of arcos(x/2)dx


If the fourth term in an arithmetic sequence is, u4 = 12.5, the tenth is u10 = 27.5. Find the common difference and the 20th term.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning