Answers>Maths>IB>Article

Differentiate, from first principles, y=x^2

According to first principles, the differential is found as the limit as h->0 of:[f(x+h)-f(x)] / hif we set our f to x^2, then we find that this expression becomes (x^2+2hx+h^2 - x^2)/hWhich simplifies to 2x+h. As h->0, this leaves us with 2x, which is the derivative of x^2

ME
Answered by Milo E. Maths tutor

1963 Views

See similar Maths IB tutors

Related Maths IB answers

All answers ▸

Find the constant term in the binomial expansion of (3x + 2/(x^2))^33


Can you explain the approach to solving IB maths induction questions?


Consider the infinite geometric sequence 25 , 5 , 1 , 0.2 , ... (a) Find the common ratio. (b) Find (i) the 10th term; (ii) an expression for the nth term. (c) Find the sum of the infinite sequence.


How to I solve system of simultaneous equations (3x3)?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences