Solve the simultaneous equations: 1) 6a+b=11 , 2) 5a-2b=19

To solve, first create a common factor for b by multiplying the 1st equation by 2 to get: 12a+2b=22.Now, add the two equations together to get: (12a+5a) + (2b-2b) = (22+19)which is 17a=41 , when simplified.Solving this we have a=41/17.Now that we have a, we can substitute this value back into one of the original equations and solve it for b.Hence, using equation 1: 6(41/17)+b=11So we get , b = 11 - 6(41/17) b = -59/17You can now check the answers by substituting both a and b into the equations.

JT

Related Maths GCSE answers

All answers ▸

How do I expand double brackets? E.g. (4x+7)(3x+5)


Where do the lines 2y = 4x + 2 and - 3x + y = 4 intersect?


James has a short drive to his garage which he wishes to pave with a single layer of bricks. If his square drive has side length 2m and James buys the bricks in stacks of 10 with each brick being 0.2m long and half as wide how many stacks must James buy?


How do I factorise x^2 ​- 4?