Solve the simultaneous equations: 1) 6a+b=11 , 2) 5a-2b=19

To solve, first create a common factor for b by multiplying the 1st equation by 2 to get: 12a+2b=22.Now, add the two equations together to get: (12a+5a) + (2b-2b) = (22+19)which is 17a=41 , when simplified.Solving this we have a=41/17.Now that we have a, we can substitute this value back into one of the original equations and solve it for b.Hence, using equation 1: 6(41/17)+b=11So we get , b = 11 - 6(41/17) b = -59/17You can now check the answers by substituting both a and b into the equations.

JT
Answered by James T. Maths tutor

3549 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Make y the subject of the formula. x=(6+2y)/(3-y)


Solve the simultaneous equations;5x +y = 21 and x-3y=9


Factorise x² + 6x + 8


3^2 + 4^2 = x^2. Find x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences