Solve the simultaneous equations: 1) 6a+b=11 , 2) 5a-2b=19

To solve, first create a common factor for b by multiplying the 1st equation by 2 to get: 12a+2b=22.Now, add the two equations together to get: (12a+5a) + (2b-2b) = (22+19)which is 17a=41 , when simplified.Solving this we have a=41/17.Now that we have a, we can substitute this value back into one of the original equations and solve it for b.Hence, using equation 1: 6(41/17)+b=11So we get , b = 11 - 6(41/17) b = -59/17You can now check the answers by substituting both a and b into the equations.

JT

Related Maths GCSE answers

All answers ▸

Factorise 15a^2 + ab - 6b^2


Washing powder is sold in two sizes: Bag 1 is 600 grams for £3.30. Bag 2 is 1500 grams and usually costs £9.60 but currently has 15% off. Which is better value?


How do you solve simultaneous equations?


Solve the simultaneous equations. 2x+5y=-4 and 7x+y=19