Solve the following two equations simultaneously: 3x + y = 10, x + y = 4

  1. Label the equations Equation 1: 3x + y = 10Equation 2: x + y = 42) Establish if the equations need to be subtracted or added together: 'Same sign is subtract and different sign is add' Therefore we need to subtract the two equations 3) Subtract Equation 2 from Equation 1 in parts 3x - x = 2xy - y = 010 - 4 = 64) Formulate new equation from results2x = 65) Solve for x In this case we need to divide by 2 to find x x = 36) Sub x = 3 back into equation 2 3 + y = 4By subtracting 3 from 4 we get y=17) Check your answer by substituting values of x and y back into equation 1 (3 x 3) + 1 ---> 9 + 1 By calculating this we achieve a result of 10 which proves that our calculation of x and y are correct
BA

Related Maths GCSE answers

All answers ▸

The equation of Line 1 is y= 3x-2, and the equation of Line 2 is 5= 9x- 3y. Are the two lines parallel?


Whats the inverse of y = 2x+1/x-1 ?


Solve the quadratic: 3x^2+4x = 20 to find x.


A washing machine costs £500 in a sale and was reduced by 20%. What was its original price?