Make h the subject of h-36=(3h+18)/i

First, multiply both sides of the equation by 'i' to remove the fraction: i(h-36) = 3h +18 Then, expand the bracket by multiplying 'i' by each of the terms inside (first h then '-36'). Make sure to keep the right sand of the equation the same. ih - 36i = 3h + 18 Now, rearrange the equation to get everything containing an 'h' on one side. You do this here by subtracting 3h from each side and adding 36i to each side. ih - 3h = 36i + 18 Factorise the left hand side so you only have one 'h' in the equation: h(i-3) = 36i +18 Now you just need to divide each side of the equation by (i-3) to leave h on its own, as the subject.h = (36i + 18)/(i-3)

RT
Answered by Rebecca T. Maths tutor

3216 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do i solve the quadratic x^2 + 5x + 6 = 0 ?


We have the following fractions: 6/16, 9/24, 12/32 and 15/35. Which fraction is not equivalent to 3/8?


Solve the following definite integral from x=2 to x=-1: ((x^4) + 3(x^2) + 2) dx


Solve (6x-2)/4 - (3x+3)/3 = (1-x)/3. (4 marks)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning