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0.0960g of Magnesium was reacted with 25cm^3 of HCL of 0.4mol/dm^3 concentration. Calculate the moles of each one and determine which one is in excess

Equations to usemoles = mass/Mrmoles= concentration*volumeAr of Magnesium = 12 Moles= 0.096/12 Moles=0.008Moles of HCL = 25/1000 x 0.4=0.1Therefore HCL is in excess

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0.0960g of Magnesium was reacted with 25cm^3 of HCL of 0.4mol/dm^3 concentration. Calculate the moles of each one and determine which one is in excess

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