Find the turning points of the curve y = 3x^4 - 8x^3 -3

Differentiate to get:dy/dx = 12x^3 -24x^2Factorise and set equal to 0:12x^2(x-2) = 0Solve to get x = 2 and x =0.

DC
Answered by Daniel C. Maths tutor

3373 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

integrate x^2 + 3x + 4


Integral of (cos(x))^2 or (sin(x))^2


I'm trying to integrate f(x)=sin(x) between 0 and 2 pi to find the area between the graph and the axis but I keep getting 0, why?


Find an equation of the curve with parametric equations x=3sin(A) and y=4cos(A), in the form bx^2+cy^2=d.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences