The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5. Work out the area of the triangle.

As we know the ratio of the sides is 3:4:5, label the sides x,y and z respectively. Side x is of length (3/12)*72, side y is of length (4/12)*72 and side z is of length (5/12)72. Giving, x = 18cm, y = 24cm, z = 30cm. Observe x is the base and z is the hypotenuse. Area of a triangle is (base x height)/2. Area = (1824)/2 = 216cm^2

VS
Answered by Viresh S. Maths tutor

2849 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you solve inequalities when they involve quadratics? i.e x^2+x-6<0


A curve has the equation y = 4x^2 + 5x + 3 and a line has the equation y = x + 2. Show that the line and the curve have one point of intersection.


Expand and simplify (x+2)(x+3)


How do you work out the gradient of a straight line?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning