How do you factorize a quadratic equation with all positive numbers?

The easiest way to approach this is by trying to find two numbers which add up to the x coefficient (the number attached before the x) and multiply to the constant (the number on its own). For example...x2 + 3x + 2 Start by finding numbers which add to make 3... 0+3 (in this case, you can't use 0 as it would get rid of the constant- any number multiplied by 0 =0)2+1 If we try multiplying to get 2 (the x coefficient)...2x1 = 2 So the numbers in the brackets must be 1 and 2. Therefore...x2 + 3x + 2 = (x+1)(x+2)

CB

Related Maths GCSE answers

All answers ▸

Solve 2x^2+7x+6=0


What is the solution to the system of equations defined by (1) x+2y = 4 and (2) y+2x = 6?


Factorise 2(x^2) +7x+3


Solve (3x +1)/x + (2x-1)/3 = -3, giving x to two decimal places.