Solve the simultaneous equations 2x + 3y = 4, 3x + 6y = 3
Label the equations (1): 2x + 3y = 4 (2): 3x + 6y = 3We need the same number of x's or y's in the equations, so multiply (1) by 3 and (2) by 2 giving (3): 6x + 9y = 12 (4): 6x + 12y = 6Subtract (3) from (4) 6x + 12y - 6x - 9y = 6 - 12 so 3y= -6 so y= -2Substitute the y value into (1) to find x 2x + (3*-2) = 4 2x - 6 = 4 2x = 10 x = 5Check by substituting into (2) (35) + (6-2) = 15 - 12 = 3 the solutions workSo x = 5 and y = -2
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