solve dy/dx = y(sec x)^2

Firstly, this differential equation should be solved using the separation of variables method, where all y terms are moved the left hand side of the equation and all x terms are moved to the right hand side. In this case, dividing both sides by y results in the equation (1/y)dy/dx = (sec x)^2. Then to find y, both sides should be integrated with respect to x, so that ∫(1/y)dy = ∫(sec x)^2 dx. The integral of 1/y with respect to y is ln y, the natural logarithm of y, and and the integral of (sec x)^2 with respect to x is tanx. Also, an arbitrary constant must be added. The resultant equation is ln y = tan x + c. This can be written explicitly in terms of y where y = e^(tan x + c) or y = Ae^(tanx) where A = e^c, another arbitrary constant.

MD

Related Maths A Level answers

All answers ▸

Let p(x) =30x^3 - 7x^2 -7x + 2. Prove that (2x+1) is a factor of p(x).


How does finding the gradient of a line and the area under a graph relate to real world problems?


Simplify ln(e^2) - 4ln(1/e)


Express X/((X+1)(X+2)) in partial fractions. OCR C4 style question