solve dy/dx = y(sec x)^2

Firstly, this differential equation should be solved using the separation of variables method, where all y terms are moved the left hand side of the equation and all x terms are moved to the right hand side. In this case, dividing both sides by y results in the equation (1/y)dy/dx = (sec x)^2. Then to find y, both sides should be integrated with respect to x, so that ∫(1/y)dy = ∫(sec x)^2 dx. The integral of 1/y with respect to y is ln y, the natural logarithm of y, and and the integral of (sec x)^2 with respect to x is tanx. Also, an arbitrary constant must be added. The resultant equation is ln y = tan x + c. This can be written explicitly in terms of y where y = e^(tan x + c) or y = Ae^(tanx) where A = e^c, another arbitrary constant.

MD
Answered by Max D. Maths tutor

7387 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A line runs between point A(5,9) and B(11,1). Find the equation of the line. Point C lies on the line between A and B. The line with equation 2y=3x+12 also crosses through point C. Find the x coordinate of Point C.


I don't understand integration by parts - can you explain it please?


Find dy/dx when y = 4x^1/2


Integrate (sin(x))^6 - Further mathematics (De Moivre's theorem)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning