Solve x^2 = 4(x-3)^2

First expand the bracket (x-3)2 separately to give x2 - 6x +9 Next multiply by the 4 outside the brackets to give 4x2 -24x +36 Now all the terms have been expanded you can collect the like terms in the equation x2 = 4x2 -24x +36 Bring the x2 to the right side of the equation to give 0 = 3x2 -24x +36 Divide this equation by 3, 0 = x2 -8x +12 (1) Factorise (1) by finding a pair of numbers that add to -8 and multiply to make 12. Both numbers need to be negative. -6 and -2 are the correct numbers. Therefore (x-2)(x-6) = 0 For this solution to equal 0 overall x must be equal to 2 or 6

JV
Answered by Joe V. Maths tutor

3351 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the Simultaneous equations. 3x+5y=22 4x-5y=6


What is the gradient of the line passing through the point (1,2) and (5,5)? What is the equation of this line? What is the equation of the line perpendicular to this line that passes through the origin (0,0)?


f(x) = (x+1)^2 and g(x) = 2(x-1); Show that gf(x) =2x(x+2)


Azmol, Ryan and Kim each played a game. Azmol’s score was four times Ryan’s score. Kim’s score was half of Azmol’s score. Write down the ratio of Azmol’s score to Ryan’s score to Kim’s score.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences