How do you find dy/dx for a set of parametric equations?

Using the chain rule:If the parameter used is 't', differentiate each equation with respect to 't' so that you have answers for dy/dt, and dx/dt.From the chain rule it is known that: "dy/dx=dy/du * du/dx". We treat dy/dt and dx/dt as fractions and so, dy/dx=(dy/dt)/(dx/dt) which gives the value for dy/dx.

FC

Related Maths A Level answers

All answers ▸

Solve, giving your answer to 3 s.f. : 2^(2x) - 6(2^(x) ) + 5 = 0


We are given y=(x^2)+3x-5. Find the derivative of y in terms of x.


A curve has equation y = 2x^5 + 5x^4 1 . (a) Find: (i) dy/ dx [2 marks] (ii) d^2y/ dx^2 (b) The point on the curve where x ¼ 1 is P. (i) Determine whether y is increasing or decreasing at P, giving a reason for your answer.


Differentiate y = xe^(2x).