Solve 5x^2 = 10x + 4 , to 2 decimal places.

First rearrange to get 5x2 - 10x - 4 = 0 , by subtracting 10x and 4 from both sides of the equation. Here, we can use the quadratic formula which is x = -b+- sqrt(b2 -4ac) / 2a. In our question a=5 , b=-10 , c=-4. Substituting these into the formula x = - (-10) +- sqrt(-102 -45-4)/2(5) =10+-sqrt(100+80) / 10 =10+- sqrt(180) / 10 So, x= 2.34, -0.34

AP
Answered by Alexander P. Maths tutor

14751 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Which of these lines are parallel to y=2x+3? Which are perpendicular? Options: 1) y=5x-4, 2) y=-1/3x+3, 3) y=-1/2x-1, 4) y=2x-2/3


find the roots of the equation 7x^2+11x-2=0 in exact form


Solve the simultaneous equations: y = x + 6, x^2 + 2y = 9


Simplify: 2x + 6y + 2y - x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning