Solve 5x^2 = 10x + 4 , to 2 decimal places.

First rearrange to get 5x2 - 10x - 4 = 0 , by subtracting 10x and 4 from both sides of the equation. Here, we can use the quadratic formula which is x = -b+- sqrt(b2 -4ac) / 2a. In our question a=5 , b=-10 , c=-4. Substituting these into the formula x = - (-10) +- sqrt(-102 -45-4)/2(5) =10+-sqrt(100+80) / 10 =10+- sqrt(180) / 10 So, x= 2.34, -0.34

AP

Related Maths GCSE answers

All answers ▸

Factorise the equation x^2 +5x = 6


How do you find the points of intersection of two curves?


Prove algebraically that 
(2n + 1)^2 – (2n + 1) is an even number for all positive integer values of n. (3 marks)


why does 4 / 0.5 =8?