A ball is released on a smooth ramp at a distance of 5 metres from the ground. Calculate its speed when it reaches the bottom of the ramp.

The ramp is smooth, so the effects of friction can be ignored. Therefore, the potential energy lost by the ball is equivalent to the kinetic energy gained by the ball. The formula for kinetic energy is 1/2 * m * v^2 and the formula for gravitational potential energy is m * g * h.Therefore, equate these and find that 1/2 * v^2 = g * h, after cancelling out m. Solving for v gets a speed of 9.90 m/s.

CB
Answered by Cameron B. Maths tutor

4489 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Show that, for all a, b and c, a^log_b (c) = c^log_b (a).


The curve C has the equation y = 1/2x^3 - 9x^3/2 + 8/x + 30, find dy/dx. Show that point P(4, -8) lies on C


Solve the simultaneous equation: y+4x+1=0 y^2+5x^2+2x=0


How do you solve the equation e^2x - 2e^x - 3 = 0 ?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning