Answers>Maths>A Level>Article

A ball is released on a smooth ramp at a distance of 5 metres from the ground. Calculate its speed when it reaches the bottom of the ramp.

The ramp is smooth, so the effects of friction can be ignored. Therefore, the potential energy lost by the ball is equivalent to the kinetic energy gained by the ball. The formula for kinetic energy is 1/2 * m * v^2 and the formula for gravitational potential energy is m * g * h.Therefore, equate these and find that 1/2 * v^2 = g * h, after cancelling out m. Solving for v gets a speed of 9.90 m/s.

Answered by Cameron B. • Maths tutor

4139 Views

See similar Maths A Level tutors

A ball is released on a smooth ramp at a distance of 5 metres from the ground. Calculate its speed when it reaches the bottom of the ramp.

Related Maths A Level answers

The curve C has equation (4x^2-y^3+3^2x)=0. The point P (0,1) lies on C: what is the value of dy/dx at P?

The height x metres, of a column of water in a fountain display satisfies the differential equation dx/dt = 8sin(2t)/(3sqrt(x)), where t is the time in seconds after the display begins. (a) Solve the differential equation, given that x(0)=0

1. The curve C has equation y = 3x^4 – 8x^3 – 3 (a) Find (i) d d y x (ii) d d 2 y x 2 (3) (b) Verify that C has a stationary point when x = 2 (2) (c) Determine the nature of this stationary point, giving a reason for your answer.

A block of mass 5kg is at rest on a smooth horizontal table, and connected to blocks of 3kg and 4kg which are hanging by strings via pulleys on either end of the table. Find the acceleration of the system and the tension in each string.

We're here to help

Company Information

Popular Requests

© MyTutorWeb Ltd 2013–2025

CLICK CEOP