In the presence of ultraviolet radiation, cyclohexane reacts with bromine. A mixture of cyclic products are formed, including C6H11Br. Discuss each step of this reaction providing equations to show the mechanism.

INITIATION: Br2 --> 2Br . The breaking of the Br2 bond from ultraviolet radiation forms two radicals, as one electron from the bond pair goes to each bromine atom. This is called homolytic fission. PROPAGATION: C6H12 + Br . --> C6H11 . + HBr C6H11 . + Br2 --> C6H11Br + Br . There are multiple TERMINATION outcomes: C6H11 . + Br . --> C6H11Br C6H11 . + C6H11 . --> C12H22 Br . + Br . --> Br2

LK
Answered by Lisa K. Chemistry tutor

18618 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

Phosphorus(III) chloride molecules are pyramidal with a bond angle less than 109.5°. Explain why a phosphorus(III) chloride molecule has this shape and bond angle.


Define the term relative isotopic mass. (2 Marks)


What is an enthalpy change?


Part a) Draw the mechanism of the attack of CN- on CH3COCH3 in the presence of HCN Part b) Explain why the product of this reaction does not rotate the plane of plane polarised light


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning