In the presence of ultraviolet radiation, cyclohexane reacts with bromine. A mixture of cyclic products are formed, including C6H11Br. Discuss each step of this reaction providing equations to show the mechanism.

INITIATION: Br2 --> 2Br . The breaking of the Br2 bond from ultraviolet radiation forms two radicals, as one electron from the bond pair goes to each bromine atom. This is called homolytic fission. PROPAGATION: C6H12 + Br . --> C6H11 . + HBr C6H11 . + Br2 --> C6H11Br + Br . There are multiple TERMINATION outcomes: C6H11 . + Br . --> C6H11Br C6H11 . + C6H11 . --> C12H22 Br . + Br . --> Br2

LK
Answered by Lisa K. Chemistry tutor

19246 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

Explain the trend in melting points of the period 3 elements


How do you calculate the pH of a weak acid?


In the presence of ultraviolet light, ethane and chlorine react to give a mixture of products. What are the products of this reaction?


Plan out a 4 step organic synthesis to form N-methyl Butanamide from 1-Bromopropane. Include relevant reagents and conditions for each reaction. Include 1 mechanism for one of the stages.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning