Solve the following simultaneous equations: 2y = 8x + 6 // x = 3y + 7

First we must try to write y as a function of x, in this case it means halving the first equation so that we find that y = 4x + 3. Once we have dicovereved this. We can now write the y in our second equation in terms of x as we just found. The second equation no would read: x = 3(4x+3) + 7 Now we expand the brackets to find that x = 12x + 9 + 7 or x = 12x + 16. This can be rearranged to the form -11x = 16 and from this we can solve for x. x = -16/11 We can then plug this into our first equation to find y.Giving us 2y = 8(-16/11) + 6 looking to find just y means we halve the whole ting to find that y = 4(-16/11) + 3 which gives us y = -31/ 11. We have now solved the whole thing giving us x = -16/11 and y = -31/11.

AH

Related Maths GCSE answers

All answers ▸

There are 720 boys and 700 girls in a school. The probability that a boy chosen at random studies French is 2/3 The probability that a girl chosen at random studies French is 3/5. Work out the number of students in the school who study French.


GCSE: How do you find the bearing of point B from A?


A shop sells bags of crisps in different size packs. There are 18 bags of crisps in a small pack (£4), 20 bags of crisps in a medium pack (£4.99) and 26 bags of crisps in a large pack (£6). Which size pack is the best value for money?


simplify 4p^3 x 3p^4