Solve the following simultaneous equations: 2y = 8x + 6 // x = 3y + 7

First we must try to write y as a function of x, in this case it means halving the first equation so that we find that y = 4x + 3. Once we have dicovereved this. We can now write the y in our second equation in terms of x as we just found. The second equation no would read: x = 3(4x+3) + 7 Now we expand the brackets to find that x = 12x + 9 + 7 or x = 12x + 16. This can be rearranged to the form -11x = 16 and from this we can solve for x. x = -16/11 We can then plug this into our first equation to find y.Giving us 2y = 8(-16/11) + 6 looking to find just y means we halve the whole ting to find that y = 4(-16/11) + 3 which gives us y = -31/ 11. We have now solved the whole thing giving us x = -16/11 and y = -31/11.

AH

Related Maths GCSE answers

All answers ▸

A group of 5 people order 2 8 inch pizzas, with heights 2cm and 1cm, and density 3/pi g/cm^3, and 5/pi g/cm^3 respectively. If they divide each pizza evenly, how much pizza, in grams, does each person eat? Use 1 inch = 2.5 cm.


What is compound interest and how do I calculate it?


What is the nth-term of this sequence? 29, 26, 23, 20, 17...


divide 352 into a ratio of 5:11