A straight line runs through these two coordinates (1,5) and (4,7), find the equation of the line.
Given that the equation is a straight line we know that it will take the form of y = mx + c with m as the gradient and c as the y-intercept. We can find the slope by doing (y1- y2)/(x1-x2) = m , if we sub in we get (5-7)/(1-4) = 2/3 we then have this eqn: y = 2/3x +c , we can then find c by subbing in either one of our coordinates: 5 = 2/3(1) + c = 13/3. The eqn of the line is: y = 2/3x + 13/3
DR
Related Maths GCSE answers
All answers ▸x^2 +y^2 =25, y – 3x = 13 - Simultaneous Equations (June 2017)
How can I tell if two lines are perpendicular from the equations?
Given that y is directly proportional to square root of x and that y = 20 when x = 49 find an expression to represent x and y.
Point A (-3,5) and point B (1,-15) are to be connected to form a straight line, fing the equation of the line in the form y=mx+c?