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A curve has equation 3x^4/3-16y^3/4=32. By differentiating implicitly find dy/dx in terms of x and y. Hence find the gradient of the curve at the point (8,1).

3x^4/3-16y^3/4=32Differentiating implicitly:4x^1/3-12y^-1/4(dy/dx)=0Simplifying and rearranging:x^1/3=3y^-1/4(dy/dx)dy/dx=1/3(x^1/3y^1/4)
Finding dy/dx using the (x,y) co-ordinates given:dy/dx=1/3(8^1/3)(1^1/4)=1/3(2)(1)=2/3

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A curve has equation 3x^4/3-16y^3/4=32. By differentiating implicitly find dy/dx in terms of x and y. Hence find the gradient of the curve at the point (8,1).

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