Solve the equation 2log (base 3)(x) - log (base 3)(x+4) = 2

First express as a single logarithm as follows. The number in front of the logarithm remembering log rules can be rewritten as the power of the number in the bracketsSo rewriting the LHS
log₃(x²) - log₃(x+4)
log₃(x²/(x+4))remember inverse log₃ is to the power of 3so2 = log₃(x²/(x+4)) 3²= (x²/(x+4))expanding and solving x²-9x-36=0(x-12)(x+3)=0x=12 as cannot do a negative logarithm of a number