Calculate the percentage, by mass, of carbon in sodium hydrogencarbonate (NaHCO3)

When faced with this style of problem there are steps to correctly answer the quesion:

Step 1 - identify the atomic mass of carbon

Step 2 - calculate the atomic mass of the compound

Step 3 - work out the percentage, by mass, of carbon in the compound

Method:

Step 1:

To  calculate the atomic mass, a periodic table is required. The atomic mass of each element is located at the top of the element, displayed as a number. In this case carbon has an atomic mass of 12 g/mol.

Step 2:

The same principles in step 1 are required and applied to the remaining atoms in the compound - sodium hydrogen carbonate. The atoms in the compound are sodium (Na), hydrogen (H), carbon (C) and oxygen (O). Looking at the value of atomic mass on the periodic table, the values of atomic mass are as follows:

Na = 23 g/mol

H = 1 g/mol

C = 12 g/mol

O = 16 g/mol

There is 1 Na atom, 1 H atom, 1 C atom and 3 O atoms in the compound. Now add these values together to get the atomic mass of the compound as such:

23+1+12+(3*16) = 84 g/mol

Step 3:

Now the percentage, by mass, needs to be calculated. The general rule for calculating a percentage is:

percentage = (value/total)*100%

Therefore by applying this rule for our problem we find that

Percentage = (12/84)*100% = 14.3 % (to 1 d.p)

HT
Answered by Hayden T. Chemistry tutor

42017 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

25cm3 of NaOH (2M) were titrated with 1.25M H2SO4. Write down the balanced reaction equation. Calculate the number of moles of NaOH used in the titration and hence deduce the volume of sulfuric acid used in the titration. Give your answer in dm3.


How do reversible reactions reach an equilibrium?


Using diagrams, describe the difference between Ionic, Covalent and Metallic Bonding.


What are the relative masses of protons, neutrons and electrons?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning