The sides of an equilateral triangle are given by the expressions x+y, 2y-1 and 3y-2x+1. Find the values of x and y.

This question test knowledge of the geometry of equilateral triangles and the students ability to solve linear equations.
First we note that an equilateral triangle has equal sides. Then we can write that x+y = 2y-1 and rearranging we find that x = y-1. Further we know that 2y-1 = 3y-2x+1 and rearranging we find that y = 2x -2. We then substitute this into the first equation we found so that x = (2x-2)-1 and rearranging once again we find that x = 3. Substituting this into y = 2x-2, we find that y = 4.

JS
Answered by Joe S. Maths tutor

8421 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the quadratic equation 4x^2 - 5x -6 = 0


Solve: x^2-x-6 using factorisation.


What is the relationship between the lengths of a right angle triangle


Show that ((√ 18 + √ 2)^2)/(√8 - 2) can be written in the form a(b + 2) where a and b are integers.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning