Draw the following inequality on a graph: x^2+4x+1<-2

First we must ensure the equation is in a form that is easy for us to plot!This means we equate the quadratic to 0 by shifting the -2 to the other side. We do this by adding +2 to both sides.Now, we draw the equation as if there is no inequality; Draw it as if there is an equals sign. This will become apparent in a little while. We know from solving it that x = -3 or x = -1. Thus when we plot the equation, the curved shape of the quadratic equation intersects the x axis (when y=0) at -3 and -1.Now, we needed to plot the INEQUALITY on the graph, not the equation. Thus, we sub in the sign again.x^2+4x+1<-2x^2+4x+3=0x^2+4x+3 < 0This statement means the equation must be less than 0. Well, we already know the equation is also in the form (x+3)(x+1) = 0(x+3)(x+1) < 0On the graph when we plot the quadratic, we see the region that satisfies this statement is the small area between the curve and the grid!