Given y=2x(x^2-1)^5, show that dy/dx = g(x)(x^2-1)^4 where g(x) is a function to be determined.

y=2x(x2-1)5 --> y=uv, where u=2x; v=(x2-1)5 --> thus product rule required.u'=2v'=10x(x2-1)4Product rule: dy/dx = uv' + v'uTherefore: dy/dx = 2x(10x(x2-1)4) + 2(x2-1)5 g(x) = (22x2-2)

SH
Answered by Sean H. Maths tutor

4436 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the integral of (cosx)*(sinx)^2 with respect to x


A matrix M has eigenvectors (3,1,0) (2,8,2) (1,1,6) with corresponding eigenvalues 1, 6, 2 respectively. Write an invertible matrix P and diagonal matrix D such that M=PD(P^-1), hence calculate M^5.


Find the equation of the tangent to the curve y^3 - 4x^2 - 3xy + 25 = 0 at the point (2,-3).


C4 June 2014 Q4: Water is flowing into a vase. When the depth of water is h cm, the volume of water V cm^3 is given by V=4πh(h+4). Water flows into the vase at a constant rate of 80π cm^3/s. Find the rate of change of the depth of water in cm/s, when h=6.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning