Given y=2x(x^2-1)^5, show that dy/dx = g(x)(x^2-1)^4 where g(x) is a function to be determined.

y=2x(x2-1)5 --> y=uv, where u=2x; v=(x2-1)5 --> thus product rule required.u'=2v'=10x(x2-1)4Product rule: dy/dx = uv' + v'uTherefore: dy/dx = 2x(10x(x2-1)4) + 2(x2-1)5 g(x) = (22x2-2)

SH

Related Maths A Level answers

All answers ▸

The equation of a circle is x^2-6x+y^2+4y=12. Complete the square to find the centre and radius of the circle.


What methods are there for integration?


The gradient of the curve at point (x,y) is given by dy/dx = [7 sqrt(x^5)] -4. where x>0. Find the equation of the curve given that the curve passes through the point 1,3.


How will you simplify (3 xsquare root of 2) to the square?