Solve the two simultaneous equations y+5x=30 and 6y=-x+64

The easiest way to solve these equations is by substitution. Rearrange the 6y=-x+64 equation into the form of x=64-6y. Replace x in the other equation with x=64-6y to produce y+5(64-6y)=30. Multiply out the brackets and rearrange to produce -29y=-290 so y=10. Substitute y=10 into the equation x=64-6y to get x=64-60 so x=4. 

HW

Related Maths GCSE answers

All answers ▸

Factorise 3x+12


Work out the integer values that satisfy: x^2−7 x+ 11<0


200 pupils are taking a school trip. Some are flying, some are taking the bus. There are three times as many boys going as girls. One third of the boys going are flying. How many boys are getting the bus?


How can I calculate the value of a number raised to the power of a fraction, e.g., 9^(3/2)?