Find the coefficient of the constant term of the expression (2x+1/(4x^3 ))^8

In order to find the coefficient we need to know which term of the binomial expansion is constant. We know the expression to find the coefficient is (8Cn)(2^n)((1/4)^(8-n)), where n is the power we are rising each variable and the variables coefficients are risen to the same power as the variables. We know both terms have a variable so we want the value n for which the variables null each other. Hence, we are looking for the term when n-3*(8-n)=0 (the -3 term comes from it being a negative power), which we can rearrange to 4n -24=0, hence n=6.Having the value of n we put it in the binomial formula and obtain the result 112.

FE
Answered by Francisco E. Maths tutor

3519 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I solve simultaneous equations? eg 1) 4x = 16 - 2y and 2) 3x + y = 9


Solve the equation: x^2 - 9x + 20 = 0


Multiply and simplify the following: (x-8)^2


A man stands 9 metres from the base of a tree. He knows the distance from where he is standing and the top of the tree is 15 metres. How tall is the tree?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning