If -3x + 10y = -100 and 13x + 10y = 60, solve for x and y.

This can be solved simultaneously. This is about manipulating the equations until they're in a format that you can use.Label the equations:eq1: -3x + 10y = -100 and eq2: 13x + 10y = 60Now, eq1 - eq2 gives us -16x + 0y = -160. The y's have cancelled out. The manipulation should always first try to remove one of the unknowns.-16x = -160, so we can remove the minus signs.x = 160/16 = 10.We can now sub x into one of the original equations. Let's use eq2.13x + 10y = 6013(10) + 10y = 60130 +10y =6010y = 60 - 130 = 70y = -70/10 = -7Therefore, x = 10, y = -7

OJ
Answered by Olyvia J. Maths tutor

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