Solve 7(k-3)=3k-5

First we need to multiply out the bracket

7k-21=3k-5

Then we must make sure our variable is only on one side so we need to deduct 3k from both sides

4k-21=-5

Now we should isolate our variable so add 21 to both sides of our equation

4k=16

Finally dividing by 4 gives us k alone

k=4

MB
Answered by Molly B. Maths tutor

14773 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand (x+2)(x-3)(x+4)^2


Solve the equation (3x + 2)/(x - 1) + 3 = 4 (3 marks)


What is the simplest form of the fraction (8a^2+10ab)/(12a+15b)?


Simplify fully 3/(2x + 12) - (x - 15)/(x^2 - 2x - 48)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning