How do you take the derivative of a^x ?

There are two ways you can take the derivative of a^x.
1) 
Let y = a^x  now we're trying to find dy/dx
2)
ln(y) = xln(a)  take logs of both sides and use log rules
3)
(dy/dx)*(1/y) = ln(a) take the derivative of both sides using the chain rule                     on the left hand side.
4)
dy/dx = ln(a)*y       multiply both sides by y
5)
dy/dx = ln(a) *a^x    realise y= a^x and replace it
Now we're done!
 
Alternatively we could realise that any exponent can be written as e to the power of something with a log in it.
So
1)
y = a^x = (e^ln(a))^x  just rewritting 'a'
2)
y = e^xln(a)        multiplying exponent rule
3)
dy/dx = ln(a)*e^xln(a) take the derivative of both sides using the chain                         rule for the right hand side
4)
dy/dx = ln(a)*a^x            substitute back to get desired result
 
 
 

SG

Related Maths A Level answers

All answers ▸

Differentiate y=x/sin(x)


Given that y = 3x(^2) + 6x(^1/3) + (2x(^3) - 7)/(3(sqrt(x))) when x > 0 find dy/dx


Given that y = (sin(6x))(sec(2x) ), find dy/dx


What is the partial fraction expansion of (x+2)/((x+1)^2)?